1/2+ 1 1/3+1 5/12 What does that equal?
$$\\{1\over 2}+ 1 {1\over 3}+1 {5\over 12}\\\\
={1\over 2}+ 1 +{1\over 3}+1 +{5\over 12}\\\\
=2+{1\over 2}+{1\over 3}+{5\over 12}\\\\
=2+
{1\over 2}
\times(
{3\over3}\times
{12\over12}
)
+
{1\over 3}
\times(
{2\over2}\times
{12\over12}
)
+
{5\over 12}
\times(
{2\over2}\times
{3\over3}
)
\\\\
=2+{5*12+5*6\over 2*3*12}\\\\
=2+{6\over6}\times{5*2+5\over 2*3*2}=2+{5*2+5\over 2*3*2}\\\\
=2+{15\over 12}=2+{3*5\over3*4}\\\\
=2+({3\over3})\times{5\over 4}=2+{5\over4}\\\\
=2+1+{1\over 4}=3+{1\over4}\\\\
=3{1\over4}$$
To solve that problem, you need to make the denominators the same. So, you add 6/12 plus 1 4/12 plus 1 5/12. So the answer is 3 1/4.
1/2+ 1 1/3+1 5/12 What does that equal?
$$\\{1\over 2}+ 1 {1\over 3}+1 {5\over 12}\\\\
={1\over 2}+ 1 +{1\over 3}+1 +{5\over 12}\\\\
=2+{1\over 2}+{1\over 3}+{5\over 12}\\\\
=2+
{1\over 2}
\times(
{3\over3}\times
{12\over12}
)
+
{1\over 3}
\times(
{2\over2}\times
{12\over12}
)
+
{5\over 12}
\times(
{2\over2}\times
{3\over3}
)
\\\\
=2+{5*12+5*6\over 2*3*12}\\\\
=2+{6\over6}\times{5*2+5\over 2*3*2}=2+{5*2+5\over 2*3*2}\\\\
=2+{15\over 12}=2+{3*5\over3*4}\\\\
=2+({3\over3})\times{5\over 4}=2+{5\over4}\\\\
=2+1+{1\over 4}=3+{1\over4}\\\\
=3{1\over4}$$