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find the equation of the line through intersection of the lines 2x-3=4 and y=x+2, passing through the point (-4,4)

Guest Jan 12, 2016

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Best Answer

solve( 2x-3=4, y=x+2 ) => {x=(7/2), y=(11/2)}

with $P_0 = ( x_0, y_0 )$ and $P_1 = (x_1, y_1)$ the equation for the line passing through P0 and P1 is:

$(y - y_0)(x_1 - x_0) = (y_1 - y_0)(x - x_0)$

or

$y=x\,\frac{y_1-y_0}{x_1-x_0}+\frac{x_1y_0-x_0y_1}{x_1-x_0}\,.$

admin Jan 12, 2016

admin · Answer 1 · 2016-01-12T05:34:43

solve( 2x-3=4, y=x+2 ) => {x=(7/2), y=(11/2)}

with $P_0 = ( x_0, y_0 )$ and $P_1 = (x_1, y_1)$ the equation for the line passing through P0 and P1 is:

$(y - y_0)(x_1 - x_0) = (y_1 - y_0)(x - x_0)$

or

$y=x\,\frac{y_1-y_0}{x_1-x_0}+\frac{x_1y_0-x_0y_1}{x_1-x_0}\,.$