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-8y(7y-2)= y2+16y

Guest Mar 7, 2017
 #1
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+5

-8y(7y-2)= y^2+16y . Did you make this one up?

 

Solve for y:
-8 y (7 y - 2) = y^2 + 16 y

Expand out terms of the left hand side:
16 y - 56 y^2 = y^2 + 16 y

Subtract y^2 + 16 y from both sides:
-57 y^2 = 0

Divide both sides by -57:
y^2 = 0

Take the square root of both sides:
Answer: |y = 0

Guest Mar 7, 2017

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