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Find the discriminant of the quadratic 5x^2 - 2x + 8 - 2x^2 + 6x + 2 - 2x^2 + 4x - 1.

 Jun 27, 2024
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If we simplify it we get \(x^2 + 8x + 9\). The discriminant is \(b^2 - 4ac\) so we get \(64 - 4\cdot9 = 28\)

 

\(28\) is the discriminant.

 Jun 27, 2024
edited by AsianMathGuy  Jun 27, 2024

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