Find the integer n such that
\(10^n = 10^{3}\sqrt{\dfrac{10^{31}}{0.001}}\)
10^n =10^3 x sqrt(10^34)
10^n =10^3 x 10^17
10^n = 10^20
n = 20
+53 We can simplify the radical to \(\frac{10^{31}}{10^{-3}}\), which equals 10^34
The square root of 10^34 is 10^17
10^17 * 10^3 = 10^20
So, n=20
