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Solve $\frac{1}{3} t - 5 < t - 2 \le -3t + 7.$ Give your answer as an interval.

Guest Jun 6, 2022

Best Answer

+515

+2

Steps:

\(\frac{1}{3}t-5

$\frac{1}{3}t-5<\:t-2\quad \::\:t>\:-\frac{9}{2}$

$t-2\le -3t+7\:\:\:\:\:\::\:t\le \frac{9}{4}$

$t>-\frac{9}{2}\quad \mathrm{and}\quad \:t\le \frac{9}{4}$

\(-\frac{9}{2}

$\:(-\frac{9}{2},\:\frac{9}{4}]$

Hope this helps!

mworkhard222 Jun 6, 2022

1⁺⁰ Answers

+515

+2

Best Answer

Steps:

\(\frac{1}{3}t-5

$\frac{1}{3}t-5<\:t-2\quad \::\:t>\:-\frac{9}{2}$

$t-2\le -3t+7\:\:\:\:\:\::\:t\le \frac{9}{4}$

$t>-\frac{9}{2}\quad \mathrm{and}\quad \:t\le \frac{9}{4}$

\(-\frac{9}{2}

$\:(-\frac{9}{2},\:\frac{9}{4}]$

Hope this helps!

mworkhard222 Jun 6, 2022

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