+769 The roots of Ax^2+Bx+1 are the same as the roots of (x - 2)(x + 2). What is A+B?
+14 Expanding \((x-2)(x+2)\) gives \(x^2 - 4\). In order to get it into the form \(Ax^2+Bx+1\) where the constant term is \(1\), we can divide the original quadratic by \(-4\) to get \(-\frac{1}{4}x^2 + 1\), so \(A+B = -\frac{1}{4} + 0 = \boxed{-\frac{1}{4}}\)
