he uses one and one half ten ounce cans of concentrate and the standard ratio of one can of concentrate to four and one third cans of cold water.How large of a pitcher does he need
+9665 volume of one and one half ten-ounce cans
= 3/2 x 10
= 15 ounce.
Let x ounce be the volume of the pitcher at least.
\(\dfrac{1}{4\dfrac{1}{3}}=\dfrac{15}{x}\\ x = \dfrac{13}{3}\times 15 = 65\)
The volume of the pitcher must be at least 65 ounce.
+129840 [4 + 1/3] cans water = [4 + 1/3]*10 ounces of water
1 + 1/2 cans of concentrate = 15 ounces of concentrate
So
[ 4 + 1/3]*10 ounces of water / 10 ounces of concentrate = ????/ 15 onces of concentrate
Multiply both sides by 15
(15/10) * [ 4 + 1/3]*10 ounces of water = 65 ounces of water
But....we need to combine the amount of water and the amount of concentrate....
So.........65 ounces of water + 15 ounces of concentrate = 80 ounce pitcher
