Help me

Woo you go Cphill!

2197^p*p-1 = 28,561^p*p-13

Using Newton-Raphson approximation,

p ≈ 0.38190388079508887........etc.

I need it simplified not answered :/ without any of those wacky formulas! 

2197^[p*(p-1)] = 28,561^[p*(p-13)]    ????

[13^3]^^[p*(p-1)]  = [13^4]^[p*(p-13)]

[ 13^3]^[p^2 - p]  = [13^4]^[p^2 -13p]

[13]^[3p^2 - 3p ]  =  [13]^[4p^2 - 52p]      bases are the same ....solve for the exponents

3p^2 - 3p  = 4p^2 - 52p    rearrange

 p^2 - 49p  = 0  factor

p ( p - 49)  = 0      set both factors to 0  and p = 0  or p  = 49

This is a diffrent question, ill post another POST to make it clearer. ;)