(a) Find the last two digits of $9*5*3$. (b) Find the last two digits of $1^{2^3}$. (By convention, exponent towers are evaluated from the top down, so $1^{2^3} = 1^{(2^3)}$.)
9 • 5 • 3 = 135 Last two digits are 35
1^(2^3) = 18 = 1 One raised to any positive power is still one,
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+2651 
