+33616 "find the derivatives of Y with respect to X , y=ln1/x(x+1)"
I assume this is \(y=\ln{\frac{1}{x(x+1)}}\) which can be expressed as \(y = -\ln{x}-\ln{(x+1)}\) using the properties of logarithms.
So we have: \(\frac{dy}{dx} = -\frac{1}{x}-\frac{1}{x+1}\) or \(\frac{dy}{dx} = -\frac{2x+1}{x(x+1)}\)
+33616 "find the derivatives of Y with respect to X , y=ln1/x(x+1)"
I assume this is \(y=\ln{\frac{1}{x(x+1)}}\) which can be expressed as \(y = -\ln{x}-\ln{(x+1)}\) using the properties of logarithms.
So we have: \(\frac{dy}{dx} = -\frac{1}{x}-\frac{1}{x+1}\) or \(\frac{dy}{dx} = -\frac{2x+1}{x(x+1)}\)
