+227 Here we go!
So, the easiest thing to do is to distribute the 2 and the 5, like so:
$$2(x+1)-5(x-3)=5 \Rightarrow 2x+2-5x+15=5$$
How'd I do this? Well, you distribute by multiplying the number outside (the 2) with each number INSIDE (the x and the 1). We also did this with the 5.
Now, let's simplify this equation.
$$2x+2-5x+15=5 \Rightarrow 2x-5x+2+15=5 \Rightarrow -3x+17=5$$
So, what I did here was put the terms with x next to each other, and those without next to each other. Then I added the like terms, which are next to each other. So, 2x-5x=-3x (Just add the coefficients, or the numbers in front of x.) and 2+15=17. Now the equation looks MUCH easier to solve. We want x all by itself, so we can subtract 17 on both sides.
$$-3x+17=5 \Rightarrow -3x+17-17=5-17 \Rightarrow -3x=-12$$
Now, that looks WAY easy. To get rid of x, we divide both sides by negative three, since division is the opposite of multiplication.
$$\frac{-3x}{-3} = \frac{-12}{-3} \Rightarrow x = 4$$
There we go! All done!
