At the local ballpark, the team charges $5 for each ticket and expects to make $1,400 in concessions. The team must pay its players $2,000 and pay all other workers $1,600. Each fan gets a free bat that costs the team $3 per bat. How many tickets must be sold to break even?
+128473 Call N the number of tickets sold...this also equals the number of bats given away...and since revenue must = expenses, we have
5N + 1400 = 2000 + 1600 + 3N simplify
2N = 2200 divide by 2 on each side
N = 1100 tickets
In order to answer the question, more information is needed: how many players are reciving $2000 each and how many workers are recieving $1,600 each. Once that information is given, you can add up the cost of what is spent on the players and workers, add the cost of the bats given away to the players, subtract the money made in concessions and then divide by the cost of the tickets to get the number of people who will need to buy a ticket to break even.
Lets say 10 players are paid $2000 each and 10 workers are paid $1600 each.
To put into an equaion, it would be ($2000)(10) + ($1600)(10) + $3X = $5X.
Since then numer of bats and the number of people are the same, bats and number of people can be represented by the same variable.
Now solve for x.
1. Multiply $2000 and 10 togother and $1600 and 10 togother. $20000 + $16000 + $3X = $5X.
2. Add $20000 and $16000 togother. $36000 +$3X = $5X.
3. Subtract 3X to both sides. $36000 = $2X
4. Divide $2 to both sides. X = 18000 people and bats
Assuming that 10 players and 10 workers are getting paid, 18,000 people will need to buy a ticket to break even.
+128473 My answer assumes that the total paid to the players and other workers is $2000 and $1600, respectively.....
Of course.....Anonymous has the correct idea if the amounts are per player and per worker.......we wouldn't have enough info to give an exact answer....
