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what is the answer to 40p^3-8p^2+5p-1

Guest Jun 1, 2017
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Solve for p:
40 p^3 - 8 p^2 + 5 p - 1 = 0

The left hand side factors into a product with two terms:
(5 p - 1) (8 p^2 + 1) = 0

Split into two equations:
5 p - 1 = 0 or 8 p^2 + 1 = 0

Add 1 to both sides:
5 p = 1 or 8 p^2 + 1 = 0

Divide both sides by 5:
p = 1/5 or 8 p^2 + 1 = 0

Subtract 1 from both sides:
p = 1/5 or 8 p^2 = -1

Divide both sides by 8:
p = 1/5 or p^2 = -1/8

Take the square root of both sides:
Answer: | | p = 1/5         or    p = i/(2 sqrt(2))         or     p = -i/(2 sqrt(2))

Guest Jun 1, 2017
edited by Guest  Jun 1, 2017

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