+0  
 
+1
215
1
avatar+545 

What is the sum of the last two digits of this portion of the Fibonacci Factorial Series: 1!+1!+2!+3!+5!+8!+13!+21!+34!+55!+89! ?

 Jul 6, 2019
 #1
avatar
+1

1!+1!+2!+3!+5!+8!+13!+21!+34!+55!+89! ?

 

=1650795 5160908461 0812169192 6245361930 9839666236 4965418549 1352072052 9574388036 7856653650 1341835411 7917542200 4740533344 6098539182 1456501250

 

Sum =5 + 0 = 5

 

Or: 1! + 1! + 2! + 3! + 5! + 8! =40,450

 Jul 6, 2019
edited by Guest  Jul 6, 2019
edited by Guest  Jul 6, 2019

17 Online Users

avatar