Find the largest positive integer $n$ such that $n^3$ divides 15.
Well, it’s obvious that every number will divide 15.
But assuming the problem means evenly divisible,
then the only solution is n = 1.
Proof: The quotient must be an integer with no remainder.
When n = 1, then n3 = 1, thus 15 / 1 = 15 This quotient does satisfy the stipulation.
n = 2, then n3 = 8, thus 15 / 8 = 1 R7 Having a remaider disqualifies the solution.
n = 3, then n3 = 27 This and all larger numbers produce a non-integer quotient.
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