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Hank started a savings account in June of 2002. On June 2006, he had $3,800. On June 2014, he had $8,600. If Hank's saving is modeled by a linear function, what was his initial deposit?

 Apr 9, 2019
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2014 - 2006 = 8 years

8,600 - 3,800 =$4,800 - Growth over 8 years

$4,800 / 8 = $600 - Linear growth per year.

2014 - 2002 = 12 years since the initial deposit.

12 x $600 = $7,200 - growth over 12-year period.

$8,600 - $7,200 = $1,400 - initial deposit in 2002.

So that the linear function would look like this:

$8,600 =$1,400 + $600n, where n is number of years since 2002.

 Apr 9, 2019

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