+109 
what is the equations for the quadratic function graphed below?
a.) y=3(x+4)^2-5
b.)y= -3(x+4)^2+5
c.) y=-3(x-3)^2-5
c.)y= 3(x-4)^2-5
+23252 The vertex is (4, -5).
If you substitute 4 for x into each of the possibilities, only (d) gives a y-value of -5; so, choose (d).
Generally speaking, if the vertex occurs at (h,k), the formula will be: y = a(x - h)2 + k.
The term a is an "expansion factor".
