Rhombus \(ABCD\), has perimeter 148, and one of its diagonals has length 24. How long is the other diagonal?
Apply Pythagroas: Other diagonal = sqrt(148^2 - 24^2) = 4*sqrt(1333).
Rhombus ABCD has a perimeter of 148, and one of its diagonals has a length of 24. How long is the other diagonal?
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Diagonal length = sqrt[ (148/4)2 - (24/2)2] * 2
