a tree broke 6 feet from the bottom if the top landed 12 feet from the base how tall was the tree before it broke
+37099 This just describes a right triangle (assuming the top is still 'connected' to the base....one leg is the base of 6 ft and one leg is the distance of 12 feet with the hypotenuse being the remaining height of the tree that must be added to the 6 foot base to get the height of the tree before it cracked and fell
Use pythagorean theorem....
a^2 + b^2 = c^2
6^2 + 12^2 = c^2
180 = c^2
c=sqrt(180) = 13.41 add this to the 6 foot base to get 19.41 feet tall before it broke.
