+220 Siva starts at vertex A of square ABCD with side length 10. He walks towards vertex C, along the diagonal AC. He then walks towards B, then towards D. What is the length of his path?
+37194 Siva walks 1 side length (10) and two diagonal lengths
The diagonal length can be found using the Pythagorean Theorem
d^2 = s^2 + s^2
d^2 = 10^2 + 10^2
d^2 = 200
d = sqrt 200 = 14.14 so total walking distance is 10 + 2 * (14.14) = 38.3 feet
