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A plane intersects the center of a sphere with a volume of about 113.1 m3. What is the area of the cross-section? Round to the nearest tenth.

area =             m2

 May 15, 2020
 #1
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Let us find the  radius of the sphere

 

113.1  = (4/3)pi r^3

 

113.1 / [ (4/3)pi ]  = r^3       take the cube root

 

r ≈  3 m

 

Then the area  of the  cross-section  is  just

 

pi * r^2   =  pi (3)^2  =  9 pi ≈  28.3 m^2

 

 

cool cool cool

 May 15, 2020

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