The equation of the line that goes through the point (1,2) and is perpendicular to the line 5x+3y=3 can be written in the form y=Mx+b where m and where b =
Slope intercept form of a line y = mx + b m = slope b = y-axis intercept (this is when x = 0)
5x + 3y = 3 re-arrange
y = -5/3x +1 m = slope = -5/3 perpindicular slope = - 1/m = 3/5
so you now have y = 3/5 x + b sub in the values x = 1 y = 2 (the point given) to calculate 'b' and you are done !!