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The equation of the line that goes through the point (1,2) and is perpendicular to the line 5x+3y=3 can be written in the form y=Mx+b where m and where b =

 Apr 11, 2020
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Slope intercept form of a line     y = mx + b     m = slope     b = y-axis intercept (this is when x = 0)

 

5x + 3y = 3    re-arrange

y = -5/3x +1    m = slope = -5/3       perpindicular slope =  - 1/m   =   3/5

 

so you now have    y = 3/5 x + b         sub in the values  x = 1   y = 2   (the point given)     to calculate 'b'  and you are done !!

 Apr 11, 2020

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