The equation of the line that goes through the point (1,2) and is perpendicular to the line 5x+3y=3 can be written in the form y=Mx+b where m and where b =

Dburgess66 Apr 11, 2020

#1**+1 **

Slope intercept form of a line y = mx + b m = slope b = y-axis intercept (this is when x = 0)

5x + 3y = 3 re-arrange

y = -5/3x +1 m = slope = -5/3 perpindicular slope = - 1/m = 3/5

so you now have y = 3/5 x + b sub in the values x = 1 y = 2 (the point given) to calculate 'b' and you are done !!

ElectricPavlov Apr 11, 2020