Multiply the numerators: \(12x^{3 \over 2} \times 5 \times 2 \times x^{1 \over 2}\times 6x^{32} = 720x^{34}\)
Multiply the denominators: \(3x^{24} \times 2x^{5 \over 2} \times 3x^{7 \over 2} = 18x^{30}\)
So, \({720x^{34} \over 18x^{30}} = \color{brown}\boxed{40x^4}\), just as proyaop found