Find the only value of x that satisfies: \sqrt{7+\sqrt{5-\sqrt{3+x}}}=3
\( \sqrt{7+\sqrt{5-\sqrt{3+x}}}=3\)
Square both sides
7 + sqrt [ 5 - sqrt (3+ x) ] = 9
sqrt [ 5 - sqrt (3 + x) ] = 2 square both sides again
5 - sqrt (3 + x) = 4
-sqrt (3 + x) = -1 square both sides one last time
3 + x = 1
x = 1 - 3 = -2
