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Find the largest value of \(c\) such that \(\frac{c^2 + 6c -27}{c-3} +2c = 23\).

 Apr 22, 2019
 #1
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Note that  c^2 + 6c - 27  factors as  (c + 9) (c - 3)

 

So   we have

 

(c + 9) (c - 3)

__________   +  2c  = 23

    c  - 3 

 

c + 9  +  2c   = 23

 

3c + 9  =   23      subtract 9 from both sides

 

3c  =  14         divide both sides by  3

 

c  = 14  / 3

 

 

cool cool cool

 Apr 22, 2019

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