If each of the variables a,b,c and d represent a different digit, and the NUMBERS(NOT multiplication of variables) abc+dca is equal to 1000, what is a+b+c+d?
+1713 so You are saying:
If each of the variables a,b,c and d represent a different digit, and abc+dca is equal to 1000, what is a+b+c+d?
Sorry I just don't understand.
Just curious.
-\(tommarvoloriddle\)
a=4, b =3, c=6, d=5
abcd =4365
abc + dca =436 + 564 =1000:
a + b + c +d =4 + 3 + 6 + 5 = 18
