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If each of the variables a,b,c and d represent a different digit, and the NUMBERS(NOT multiplication of variables) abc+dca is equal to 1000, what is a+b+c+d?

off-topic
 Jul 11, 2019
edited by Guest  Jul 11, 2019
 #1
avatar+1342 
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so You are saying:

 

 

If each of the variables a,b,c and d represent a different digit, and abc+dca is equal to 1000, what is a+b+c+d?

 

Sorry I just don't understand.

Just curious.

-\(tommarvoloriddle\)

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 Jul 11, 2019
 #2
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+2

a=4, b =3,  c=6,  d=5

abcd =4365

abc + dca =436 + 564 =1000:

a + b + c +d =4 + 3 + 6 + 5 = 18

 Jul 11, 2019
 #3
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+5

Good Job Guest

tommarvoloriddle  Jul 11, 2019
 #4
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Thank you SO much, guest!

 Jul 12, 2019
 #5
avatar+1342 
+1

wait. So you are a different guest? this is confusing...

tommarvoloriddle  Jul 12, 2019

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