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AD=AE$\Rightarrow$ triangle ADE is an isosceles triangle. $\Rightarrow$ angle ADE= angle AED=(180-56)/2=62 degrees

BA || CE $\Rightarrow$ angle BAD = angle ADE = 62 degrees

BA || CE $\Rightarrow$ BA || CD and CB || DA by given $\Rightarrow$quadrilateral BCDA is a parallelgram

angle BCD = angle BAD = 62 degrees (opposite angles of parallelgram are equals)