+584 AD=AE\(\Rightarrow\) triangle ADE is an isosceles triangle. \(\Rightarrow\) angle ADE= angle AED=(180-56)/2=62 degrees
BA || CE \(\Rightarrow\) angle BAD = angle ADE = 62 degrees
BA || CE \(\Rightarrow\) BA || CD and CB || DA by given \(\Rightarrow\)quadrilateral BCDA is a parallelgram
angle BCD = angle BAD = 62 degrees (opposite angles of parallelgram are equals)
