Nicholas has two times as many quarters as pennies and three times as many dimes as pennies. Nicholas has a total of forty-two pennies, dimes and quarters. The total value of the coins is $5.67. How many of each coin does he have?
+113 2 = quarters
3 = dimes
total coins = 42
3 * 2 = 6
42 / 6 = 7
pennies = 7
7 * 2 = 14
quarters = 14
7 * 3 = 21
dimes = 21
+1223 Let p = the number of pennies, d = the number of dimes, and q = the number of quarters. We can set up a system of equatoins:
p + d + q = 42 (eq. 1)
q = 2p (eq. 2)
d = 3p (eq. 3)
p + 10d + 25q = 567 (eq. 4)
Plug in the results of equations 2 and 3 into equation 1.
p + 3p + 2p = 42
6p = 42
p = 7
d = 3p = 21
q = 2p = 14
