Nicholas has two times as many quarters as pennies and three times as many dimes as pennies. Nicholas has a total of forty-two pennies, dimes and quarters. The total value of the coins is $5.67. How many of each coin does he have?

Guest Jan 30, 2022

#1**0 **

2 = quarters

3 = dimes

total coins = 42

3 * 2 = 6

42 / 6 = 7

pennies = 7

7 * 2 = 14

quarters = 14

7 * 3 = 21

dimes = 21

tacoBRO1023 Jan 30, 2022

#2**+1 **

Let p = the number of pennies, d = the number of dimes, and q = the number of quarters. We can set up a system of equatoins:

p + d + q = 42 (eq. 1)

q = 2p (eq. 2)

d = 3p (eq. 3)

p + 10d + 25q = 567 (eq. 4)

Plug in the results of equations 2 and 3 into equation 1.

p + 3p + 2p = 42

6p = 42

p = **7**

d = 3p = **21**

q = 2p = **14**

CubeyThePenguin Jan 30, 2022