Let \[f(x) = \left\{ \begin{array}{cl} x^2+1 &\text{ if }x>5, \\ 2x-3 &\text{ if } -5 \le x \le 5, \\ 3 &\text{ if } x <-5. \end{array} \right.\]
Find $f(-7)+f(0)+f(7)$
-7 is less than -5 so f(-7)=3
You can try the other 2