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A cannonball is fired on flat ground at 420m/s at a 53 degree angle. What maximum height does it reach?

 Jan 12, 2021
 #1
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Max height  =   (v^2  *  sin ^2(theta) ) / (2 *9.81)  =

 

               (420)^2 *  [ sin (53°) ]^2   /  [ 2 *9.81]  =  5734.52 m

                       

                              

 

 

cool cool cool 

 Jan 12, 2021

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