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Help on simplifying radicals (square roots)

1) 4 / √32

2) 5 / √48

3) 3√5 / √25

4) 3√24 / √2


Please help me, I've ben stuck on these problems for days. Thank you very much in advance!

 Jul 29, 2014

Best Answer 

 #3
avatar+26393 
+5

1) 4 / √32   ?

$$\boxed{\dfrac{4 }{ \sqrt{32} }} \\ \\
=\dfrac{\sqrt{16} }{ \sqrt{32}} \\ \\
=\sqrt{ \dfrac{16 }{ 32} } \\ \\
=\sqrt{ \dfrac{1 }{ 2} } \\ \\
=\dfrac{1}{\sqrt{2} } * \dfrac{\sqrt{2}}{\sqrt{2}}\\\\
\boxed{=\dfrac{\sqrt{2}}{2}}$$

 Jul 30, 2014
 #1
avatar+4473 
+5

1) 4 / sqrt(32) =

4 / sqrt(4*8) =

4 / [sqrt(4)*sqrt(8)]=

4 / [2*sqrt(8)] =

2/ sqrt(8) * [sqrt8/sqrt8] =

2sqrt8/8 =

sqrt8/4.

 

2) 5 / sqrt(48) = 

5 / sqrt(16*3) = 

5 / [sqrt(16)*sqrt(3)] =

5 / [4*sqrt(3)] =

5 / 4sqrt3 * [sqrt3 / sqrt3] =

5sqrt3 / 12.

 

3) 3sqrt5 / sqrt(25) =

3sqrt5 / 5.

 

4) 3sqrt24 / sqrt(2) =

3*sqrt(2)*sqrt(12) / sqrt(2) =

3sqrt(12).

 Jul 29, 2014
 #2
avatar+26393 
+6

4) 3√24 / √2   ?

 $$\boxed{\dfrac{3 *\sqrt{24} }{ \sqrt{2} }} \\ \\
=3 *\sqrt{ \dfrac{24 }{ 2} } \\ \\
=3 *\sqrt{ 12 } \\ \\
=3 *\sqrt{ 4*3} \\ \\
=3 *\underbrace{\sqrt{ 4}}_{2}*\sqrt{3} \\ \\
=3 *2*\sqrt{3} \\ \\
\boxed{=6\sqrt{3}}$$
  

 Jul 30, 2014
 #3
avatar+26393 
+5
Best Answer

1) 4 / √32   ?

$$\boxed{\dfrac{4 }{ \sqrt{32} }} \\ \\
=\dfrac{\sqrt{16} }{ \sqrt{32}} \\ \\
=\sqrt{ \dfrac{16 }{ 32} } \\ \\
=\sqrt{ \dfrac{1 }{ 2} } \\ \\
=\dfrac{1}{\sqrt{2} } * \dfrac{\sqrt{2}}{\sqrt{2}}\\\\
\boxed{=\dfrac{\sqrt{2}}{2}}$$

heureka Jul 30, 2014

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