+0  
 
0
3
199
3
avatar+-11 

 A right isosceles triangle is a triangle with two sides that are equal in length and are perpendicular to each other. The medial triangle of triangle ABC is the triangle whose vertices are the midpoints of the sides of triangle ABC. Prove that the medial triangle of a right isosceles triangle is also a right isosceles triangle.

 Nov 20, 2020
 #1
avatar+116126 
+2

Let  triangle  ABC  be an isoscelses right  triangle with equal  legs  AC  and BC  and hypotenuse  BA

Since E and D split sides AC and AB proportionally  (they are midpoints), then ED is parallel to BC

And for the same reason DF is parallel to AC  and EF is parallel to AB

And angle AED  = angle ACB   = 90

And since EF is parallel to AB, then angle EFC = angle ABC 

But EF is a transversal cutting parallel segments , so angle EFC = angle FED

So angle FED also equals angle ABC

And since Dfis parallel to CA, then angle DFB = angle ACB  = 90

And angle DBF = angle ABC 

So, by AA congruency, triangle DFB is similar to triangle ACB

And angle FDB = angle CAB

But DF is a transversal cutting parallels ED and CB......

Then angle EFD  = angle FDB

But FDB = angle CAB

So angle CAB  = angle EFD

 

So angle CAB = EFD

And angle  ABC  = angle  FED

But CB = AC  so  angles CAB and ABC are equal

So  angle EFD  and FED are equal

So triangle EFD is similar to triangle  CAB  by AA congruency

And since ABC is an isosceles right triangle, median triangle FDE is also an isosceles right triangle

 

 

cool cool cool

 Nov 20, 2020
 #2
avatar-11 
0

wow! I never thought I would see THE CPhill in my questions. Anyways, thanks so much for the detailed help!

jeffthememeguy  Nov 20, 2020
 #3
avatar+116126 
0

OK man.....glad to help   !!!

 

 

cool cool cool

CPhill  Nov 20, 2020

70 Online Users

avatar
avatar