+0  
 
+1
97
1
avatar

Give an example of a quadratic function that has zeroes at x=2 and x=4, and that takes the value 6 when x=3.

Enter your answer in the expanded form "ax^2 + bx + c", where a,b,c are replaced by appropriate numbers.

Guest Feb 13, 2018
 #1
avatar+86944 
+1

We can write this form, first

 

Since   x = 2  and x  = 4 are zeroes we know that it will factor as

 

y  =  a ( x - 2) (x - 4)     so.....when x  = 3  , y = 6    and we can solve for "a"

 

6 = a(3 - 2) ( 3 - 4)

 

6  = -1 a   ⇒     a = -6

 

So.....the fumction is

 

y  = -6 ( x - 2)(x - 4)

 

y  =  -6 (x^2 - 6x  + 8)

 

y = -6x^2 +36x - 48

 

 

Here's a graph to confirm this :

 

https://www.desmos.com/calculator/q6hbimtgh1

 

 

cool cool cool

CPhill  Feb 13, 2018

10 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.