The number 66 is written as the sum of two smaller numbers. One of the numbers is 3 more than twice the other number. Find the larger of the two numbers?
We can set up an equation, here:
First number= \(x\)
Second number=\(2x+3\)
So, \(x+2x+3=66\)
Simplifying more, we have:
\(3x+3=66\)
\(3x=63\)
\(x=21\)
Since it's asking for the larger number, we simply do:
\(21*2+3=\boxed{45}\)
That looked harder so let me tell you my way:
3*22=66
easy peasy lemon squeasy
That is wrong; 3*2+3=9, not 22
+884 
