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The number 66 is written as the sum of two smaller numbers. One of the numbers is 3 more than twice the other number. Find the larger of the two numbers?

We can set up an equation, here:

First number= \(x\)

Second number=\(2x+3\)

So, \(x+2x+3=66\)

Simplifying more, we have:

\(3x+3=66\)

\(3x=63\)

\(x=21\)

Since it's asking for the larger number, we simply do:

\(21*2+3=\boxed{45}\)

That looked harder so let me tell you my way:

3*22=66

easy peasy lemon squeasy

That is wrong; 3*2+3=9, not 22