+37 I am not sure which formula to use for these. I've tried a few different ways and cannot get the correct answer.
1. If a force of 6.0 N acted on a 0.50-kg block for a distance of 8.0 m, what would be the velocity of the block? (Assume the block is initially at rest.)
2. (a) What is the kinetic energy in joules of a 1080-kg automobile traveling at 96 km/h?
(b) How much work would have to be done to bring a 1080-kg automobile traveling at 96 km/h to a stop?
+37153 Work = force x distance
6 N x 8 M = 48 N-M
Kinteic enrgy = 1/2 mv^2 = work = 48 N-M (the m in 1/2 mv^2 is the mass)
= 1/2 (.5 kg) v^2 = 48 N-M
so v= 13.86 M/s
2: KE = 1/2 1080 kg *( 96 km/hr * 1000m/km * 1hr/3600sec)^2 = 384 kj
(the stuff in red is converting to m/s from km/hr kj=kilojoule)
The work required to stop the auto is equal to the K.E 384 kj
