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   2                       6

______      +      ____

4v - 12                 2

Note....that we can reduce the first fraction by dividing each term by 2

And the second fraction reduces to   3 / 1

So we have

   1                  3

____      +     ____ 

2v - 6               1

Cross- multiplying in the order   1*1  +  3(2v - 6)  ⇒   1 + 6v - 18 ⇒ 6v - 17

Multiply the denominators  (2v - 6) * 1  =   2v - 6

So   we have

6v - 17

______      and you are through  !!!!!

2v - 6