\(\frac{2}{6}-\frac{n+1}{2n+3}\)
I'm trying so hard to do these but I just can't >.<
Using my method cited on your other post
The first fraction reduces to 1 / 3
So we have
1 - n + 1
__ ______
3 2n + 3
Cross-multiply in this order 1 (2n + 3) - 3(n + 1) ⇒ 2n + 3 - 3n - 3 ⇒ -n
Multiply the denominators
3 ( 2n + 3) = 6n + 9
So...we have
-n
_____ and you are finished !!!!
6n + 9