\(\frac{2}{6}-\frac{n+1}{2n+3}\)

I'm trying so hard to do these but I just can't >.<

RainbowPanda Nov 5, 2018

#1**+2 **

Using my method cited on your other post

The first fraction reduces to 1 / 3

So we have

1 - n + 1

__ ______

3 2n + 3

Cross-multiply in this order 1 (2n + 3) - 3(n + 1) ⇒ 2n + 3 - 3n - 3 ⇒ -n

Multiply the denominators

3 ( 2n + 3) = 6n + 9

So...we have

-n

_____ and you are finished !!!!

6n + 9

CPhill Nov 5, 2018