A point (x,y) is chosen at random inside the square with vertices (0,0), (0,1), (1,1), (1,0). What is the probability that x^2+y^2<1?
Please explain because I want to know how you got the answer!
+2668 Note that the equation is a circle centered at (0, 0) with a radius of 1.
Using this, we can draw a diagram representing the outcomes:
Basically, the shaded region (red) is the area of the success and the black square (side length 1) is the area of the total region
Can you take it from here?
I need the whole explanation. This is due soon.
Can you give the complete explanation?
And solve this one too: https://web2.0calc.com/questions/please-help-please-explain-your-answer
+2668 Alright. Notice that the red-shaded region is a quarter circle with a radius of 1. This means that its area is \((1^2 \pi) \div 4 = {\pi \over 4}\)
The area of the square is just 1 x 1 = 1, so the probability is just \(\color{brown}\boxed{ \pi \over 4}\)
