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What is the smallest positive $n$ such that $\frac{n}{2010}$ is a terminating decimal?

 Aug 19, 2020
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2010 = 2 * 3 * 5 * 67

201 = 3 * 67

 

Therefore, the amallest positive n =201

201 / 2010 = 1/10 =0.1

 Aug 19, 2020

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