Hi could someone help me out? It would mean a lot to me.
In quadrilateral BCED, we have BD = 11, BC = 9, and CE = 2. Sides BD and CE are extended past B and C, respectively, to meet at point A. If AC = 8 and AB = 5, then what is DE?
By similar triangles, DE = 1/2*(11 + 9)*(8 - 5)/2 = 15.