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Let a1, a2 ,a3,...be an arithmetic sequence.

 

If \(a_{23} = \dfrac23 and a_{53} = \dfrac32 what is a_{35} \)

 May 9, 2022
 #1
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\(a_{35} = 6/5\)

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 May 9, 2022
 #2
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I already tried that. It's not it. im soo confused

Guest May 9, 2022
 #3
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+1

 

you use the formula     Tn=a+(n-1)d

 

\(a+22d=\frac{2}{3}\qquad (1)\\ a+52d=\frac{3}{2}\qquad (2)\\~\\ (2)-(1)\\ 30d=\frac{3}{2}-\frac{2}{3}\\ 30d=\frac{5}{6}\\ d=\frac{1}{36}\\ \)

 

Check what i have done, then sub d in to find a

 

Then find  a35

 

Any questions? , then i am happy to discuss further.

 May 9, 2022

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