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# Help please! In what quadrant does the terminal ray of the angle lie?

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In what quadrant does the terminal ray of the angle lie?

−21π/8

−5π/9

5π/6

35π/4

Mar 18, 2020

#1
+25450
+1

In what quadrant does the terminal ray of the angle lie?

−21π/8

−5π/9

5π/6

35π/4

$$\begin{array}{|r|cll|} \hline \text{Quadrant} \\ \hline I. & 0^\circ \cdots 90^\circ \\ II. & 90^\circ \cdots 180^\circ \\ III.& 180^\circ \cdots 270^\circ \\ IV. & 270^\circ \cdots 360^\circ \\ \hline \end{array}$$

$$\begin{array}{|c|c|c|r|} \hline & \text{degrees} & & \text{Quadrant} \\ \hline -\dfrac{21\pi}{8} & -\dfrac{21}{8}*180^\circ=-472.5^\circ & -472.5^\circ+2*360^\circ = \mathbf{247.5^\circ} & III \\ \hline -\dfrac{5\pi}{9} & -\dfrac{5}{9}*180^\circ=-100^\circ & -100^\circ+360^\circ = \mathbf{260^\circ} & III \\ \hline \dfrac{5\pi }{6} & \dfrac{5}{6}*180^\circ=\mathbf{150^\circ} & & II \\ \hline \dfrac{35\pi }{4} & \dfrac{35}{4}*180^\circ=\mathbf{135^\circ} & & II \\ \hline \end{array}$$

Mar 18, 2020