+16 The range of the function \(f(x)\) is \([-3,5]\). Let \(g(x)=[f(x)]^2\). Find the range of the function \(g(x)\).
Thanks!
+16 Wait, but @ikleyn, check out my answer here:
Let \(y=f(x)\), so \(y\) can take on any value from \(-3\) to \(5\), inclusive. Then, \(y^2\) can take on any value from 0 to 25, inclusive. )If we take any value from \(-3\) to \(0\) and square it, we get a value from 0 to 9. And if we take any value from 0 to 5 and square it, we get a value from 0 to 25.) Therefore, the range of \(g(x)\) is \(\boxed{[0,25]}\)
