help please,,,its urgently needed

3^p = 3^2(27)^q

3^p = 3² (3³)^q

3^p= 3² (3^3q)

3^p = 3^(2+3q)

   so   p = 2 + 3q

log₂7 - log₂ (11q-2p) = 1     sub in    p = 2 + 3q

log₂7 - log₂ (11q-4-6q) = 1

log₂7 - log₂ (5q-4) = 1                        convert to log₁₀

log 7 /log2  - log(5q-4)/log2 = 1

log 7 - log (5q-4) = log2

log (5q-4 ) = log2 - log 7

5q-4 = .2857

q=.857142          then p = 4.571429