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# HELP PLEASE!! DUE TOMORROW!! Need Help on 3 questions!

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All help is appreciated. If you only know one question please still submit it. I need all the help I can get. Thanks! 1) In the multipication question below, find the product abcd:

7 a

x  b 6

a  a  a

6   6   6

7   d   c  a

2) The function a*b is defined as a*b = a2b-a+b. Find the value of 2*(1*(2*(1*(2*1)))).

3) Find the sum of the proper divisors of the sum of the proper divisors of the number 432.

Jan 20, 2019
edited by Dominator416  Jan 20, 2019

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1) a = 4, b = 9, You should be able to work out c and d easily from this.

3) 722.  I just used WolframAlpha to answer this. (Edited to correct answer - see asdf below).

Jan 20, 2019
edited by Alan  Jan 20, 2019
edited by Alan  Jan 20, 2019
edited by Alan  Jan 20, 2019
edited by Alan  Jan 20, 2019
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isnt 808 the sum of the proper divisors of 432?

i thought you had to do it twice.

so you would have 2^3*101

then using formulas, you get 15*102 or 1530

then take away 808 to get 722.

Jan 20, 2019
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You are correct. I wrote down the wrong number from WolframAlpha!

Alan  Jan 20, 2019
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ok thanx

asdf335  Jan 20, 2019
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and number 2: keep your work organized and solve

Jan 20, 2019
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ok so number two.

1. calculate the first 2*1

2*1 is 4-2+1 or 3.

2. now you have 2*(1*(2*(1*3))).

calculate 1*3.

1*3 is 3-1+3 or 5.

3. now you have 2*(1*(2*5)).

calculate 2*5.

2*5 is 20-2+5 or 23.

4. now you have 2*(1*23).

calculate 1*23.

1*23 is 23-1+23 or 45.

5. just calculate 2*45.

this is 180-2+45 or 225-2 or 223.

HOPE THIS HELPED!

Jan 20, 2019
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asdf is correct! Good job! 722.

.
Jan 20, 2019
edited by tertre  Jan 20, 2019
edited by tertre  Jan 20, 2019
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Thanks You All I really apretiate it!!!! Jan 20, 2019
#9
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No problem, we are here to help!

tertre  Jan 20, 2019
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tertre you have to do it again with the same logic and get 722.

lol :P

Jan 20, 2019