+0

+5
72
4
+759

Let $S = \frac{1}{2^3} + \frac{1}{4^3} + \frac{1}{6^3} + \dotsb$and $T = \frac{1}{1^3} + \frac{1}{3^3} + \frac{1}{5^3} + \dotsb.$Find $S/T$.

Feb 15, 2020

#1
0

S = Sum[1/n^3; n = 0; n = n + 2; n <= inf] = 1/4*zeta(5) and T = Sum[1/n^3: n = 1; n = n + 2; n <= inf] = 3/4*zeta(5), so S/T = 1/3.

Feb 15, 2020
#3
+1

S = 0.15025711289495
T=1.051799790264645
S/T =0.15025711289495 / 1.051799790264645
S/T = 1 / 7

Feb 15, 2020
#4
+108771
-1

Why don't you put your Latex into the Latex box so that people can read it  ?

Feb 15, 2020