In triangle ABC, CA=4sqrt(2), CB=4sqrt(3), and A=60 degrees. What is B in degrees?
+128475 C
4sqrt 2 4sqrt 3
A 60 B
Using the Law of Sines
sin A /BC = sin B / AC
sin 60 / (4sqrt (3) ) = sin B / (4sqrt 2)
sqrt (3) / 2 sin B
________ = ______
4sqrt 3 4sqrt 2
(1 / 8) = sin B / 4sqrt 2
(1/8) = sin B / 4sqrt 2
4sqrt 2
______ = sin B
8
sqrt (2) / 2 = sin B
B = 45°
