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Solve the system

3x+2y=−13x+2y=−1

x−2y=5

Guest Sep 20, 2018
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We have 3x+2y=−13x+2y=−1 and x−2y=5.

Simplifying the first equation: 3x+2y=-13x+2y, 16x=0y, so 16x=-1, and x=-1/16.

Plugging the value of x in our second equation: \(\frac{-1}{16}-2y=5, -2y=\frac{81}{16}, 2y=\frac{-81}{16}, y=\frac{-81}{32}.\)

tertre  Sep 20, 2018

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