Solve the system
3x+2y=−13x+2y=−1
x−2y=5
We have 3x+2y=−13x+2y=−1 and x−2y=5.
Simplifying the first equation: 3x+2y=-13x+2y, 16x=0y, so 16x=-1, and x=-1/16.
Plugging the value of x in our second equation: \(\frac{-1}{16}-2y=5, -2y=\frac{81}{16}, 2y=\frac{-81}{16}, y=\frac{-81}{32}.\)
