help please!

We have 3x+2y=−13x+2y=−1 and x−2y=5.

Simplifying the first equation: 3x+2y=-13x+2y, 16x=0y, so 16x=-1, and x=-1/16.

Plugging the value of x in our second equation: $\frac{-1}{16}-2y=5, -2y=\frac{81}{16}, 2y=\frac{-81}{16}, y=\frac{-81}{32}.$