If the quadratic x^2+4mx+m has exactly one real root, find the positive value of m.
Thanks!
If the quadratic has exactly one real root then the discriminant must be zero.
(4m)2 - 4(1)(m) = 0
16m2 - 4m = 0
m(16m - 4) = 0
16m - 4 = 0 or m = 0
16m = 4
m = 1/4
The positive value of m is 1/4
thanks!
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