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If the quadratic x^2+4mx+m has exactly one real root, find the positive value of m.

Thanks!

 Jun 8, 2019

Best Answer 

 #1
avatar+8215 
+2

If the quadratic has exactly one real root then the discriminant must be zero.

 

(4m)2 - 4(1)(m)  =  0

 

16m2 - 4m  =  0

 

m(16m - 4)  =  0

 

16m - 4  =  0          or          m  =  0

 

16m  =  4

 

m  =  1/4

 

The positive value of  m  is  1/4

 Jun 8, 2019
 #1
avatar+8215 
+2
Best Answer

If the quadratic has exactly one real root then the discriminant must be zero.

 

(4m)2 - 4(1)(m)  =  0

 

16m2 - 4m  =  0

 

m(16m - 4)  =  0

 

16m - 4  =  0          or          m  =  0

 

16m  =  4

 

m  =  1/4

 

The positive value of  m  is  1/4

hectictar Jun 8, 2019
 #2
avatar+248 
+2

thanks!

sinclairdragon428  Jun 8, 2019

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